solve it urgently please
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Given a triangle ABC right angled at B
tan theta = 1
=tan theta = tan 45°
=theta = 45°
other angle also be 45° (by angle sum property )
Now 2 sin theta cos theta = 1
Taking LHS
= 2 sin 45° cos 45°
= 2 ×1/√2 × 1/√2 = 1 [sin 45° = 1/√2. also cos 45° = 1/√2]
= LHS = RHS
proved
tan theta = 1
=tan theta = tan 45°
=theta = 45°
other angle also be 45° (by angle sum property )
Now 2 sin theta cos theta = 1
Taking LHS
= 2 sin 45° cos 45°
= 2 ×1/√2 × 1/√2 = 1 [sin 45° = 1/√2. also cos 45° = 1/√2]
= LHS = RHS
proved
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