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limt x tends to pai by 2
(cos{teata}÷[pai by 2 - teata])
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Using L'Hopital Rule, limit becomes,
-2sin 2x/(-1)=-2/(-1)=2
-2sin 2x/(-1)=-2/(-1)=2
Ajnas1:
cos 2 teata by (pai by2 - teata)
okay
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