Question

solve linear equation 5x-3y=1 2x+5y-15=0

Answer 1

Answer:

5x-3y=1.........(1) *5

2x+5y=15......(2)*3

Step-by-step explanation:

multiply equation (1) by 5 and equation (2) by 3

25x-15y=5.......(3)

6x+15y=45.....(4)

then,

eqn(4) - eqn(3)

-19x=40

x= -40/19

Answer 2

Answer:

x = 50/31

y = 73/31

Step-by-step explanation:

Given :

5x - 3y = 1

2x + 5y - 15 = 0

To find :

value of x and y.

Solution:

let the equation 5x - 3y = 1 is equation (1)

and the equation 2x + 5y  = 15 is equation (2)

The next step is to equalise both the equations

so we will have to eliminate either x or y.

Here we will multiply equation (1) with 5 and equation (2) with 3.

5x - 3y = 1 → (1) x 5

2x + 5y  = 15. → (2) x 3

so now equations will be

25x - 15 y = 5 → (3)

6x + 15y = 45 → (4)

Now we will add equation (4) and equation (3)

25x - 15 y = 5

6x + 15y = 45

_____________

31 + 0 = 50

_____________

31x = 50

x = 50/31

substituting value of x in equation (1) we get

5(50/31) - 3y = 1

250/31 - 3y = 1

3y = 250/31 - 1

3y =  219/31
y = 73/31

Hence value of x = 50/31

y = 73/31

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