solve log tanx. plz it's urgent
adityajadhav192005:
hi
hii jaanu
kuch to bolo
are u hear
online aau na
plzzz
dear......naraj hogi kya
Answers
Answered by
2
log tan x
Assume tan x to be y then the question becomes to find the derivative of log y.
Hence, d/dx log (tan x) = 1/tan x . d/dx (tan x) ( using d/dx log x = 1/x)
= 1/tan x . sec2 x.
= (cos x)/ (sin x). 1/ cos2x
= 1/ sin x cos x
This is the answer which if required can further be simplified as 2/ 2sin x cos x
which becomes 2/ sin 2x = 2 cosec 2x.
Assume tan x to be y then the question becomes to find the derivative of log y.
Hence, d/dx log (tan x) = 1/tan x . d/dx (tan x) ( using d/dx log x = 1/x)
= 1/tan x . sec2 x.
= (cos x)/ (sin x). 1/ cos2x
= 1/ sin x cos x
This is the answer which if required can further be simplified as 2/ 2sin x cos x
which becomes 2/ sin 2x = 2 cosec 2x.
uuu
yes
me
stopping all chats ,u wanna become doc na
so just go and study
byy
u also have to become doctor na
go nd study
i know what i'm doing
good
Similar questions