Question

Solve:- log(x+1) base2 - log(3x-1) base2=2​

Answer 1

Step-by-step explanation:

$log_{2 }(x + 1) - log_{2}(3x - 1) = 2$

$log_{2}(x + 1 \div 3x - 1) = 2$

$log_{2}(x + 1 \div 3x - 1) = log_{2}(4)$

By comparison

$x + 1 \div 3x - 1 = 4$

$x + 1 = 12x - 4$

$11x = 5$