Question

solve logx + log(x-1)= log(3z+12)

Answer 1

Answer:

x=6 or x=-2

Step-by-step explanation:

log(x(x-1))=log(3x+12)

$x^{2}$-x=3x+12

$x^{2}$-4x-12=0

$x^{2}$-6x+2x-12=0

x(x-6)+2(x-6)=0

(X-6)(x+2)=0

x=6 or x=-2