Question

solve: logx+log (x-5)=log6​

Answer 1

Answer:

logx+log (x-5)=log6

Log x(x-5) = Log 6

x(x-5) = 6

${x}^{2} - 5x - 6 = 0$

${x}^{2} - 6x + x - 6 = 0$

x(x-6)+1 (x-6) = 0

(x+1)(x-6)=0

x= -1 , 6

x=6 ( As, x is not equal to -1 )