Solve my 11 number problem.
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Given : 108a² - 3(b - c)²
⇒ 3[36a² - (b - c)²]
⇒ 3[(6a)(6a) - (b - c)²]
⇒ 3[(6a)² - (b - c)²]
We know that : a² - b² = (a + b)(a - b)
⇒ 3[(6a + b - c)(6a - b + c)]
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