Question

The function f(x)=4sin3x−6sin2x+12sinx+100 is strictly

Answer 1

Hence its clear that the function is strictly decreasing in the interval.(π2,π)(π2,π)Hence B is the correct answer.Step 1f(x)=4sin3x−6sin2x+12sinx+100
Step 2When x=π2,f′(x)=0x=π2,f′(x)=0when x=π,f′(x)=−12