Math, asked by grilo, 1 year ago

solve my above question ....​

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Answered by rishabhappbuilter210
0

Step-by-step explanation:

The ratio of the radius of electron's orbit to the radius of nucleus is

10-^10m/10-^15m)= 10^5. That is the radius of the electron's orbit is 105 times larger than the radius of nucleus. If the radius of the earth's orbit around the sun were 10^5 times larger than the radius of the sun, the radius of the earth's orbit would be10^5× 7 × 10^8m = 7 × 10^13m. This is more than 100 times greater than the actual orbital radius. Thus the earth would be much farther away from the sun. It implies that an atom contains a much greater fraction of empty space than our solar system does.

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Answered by missShelly
4

ᾰṧ-ṧᾰℓᾰՊ ᾰℓ!кṳՊ!!

radius of Earth orbit /radius of nucleus

= 10^-10 / 10^-15

= 10^5

radius of earth = 10^5 × 7 × 10^8

= 7× 10^-13 m

✍️ an atom is Greater empty space than that of solar system.

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