Physics, asked by aman691980, 11 days ago

solve my problem... .​

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Answered by mahanteshgejji
1

Answer:

P = \sqrt{2 K m}

Explanation:

K = \frac{1}{2} mv² = \frac{1}{2} mv² x \frac{m}{m} = \frac{1}{2} m²V² x \frac{1}{m} = \frac{1}{2m} x P²

∴ P² = 2mK

  P = \sqrt{2 m K}

Answered by itzchocolatelover32
0

Answer:

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