Math, asked by mishraamit46694, 5 hours ago

solve my question and earn point ​

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Answers

Answered by rashmirekhakundu02
0

Answer:

180-80=100 (vertically opposite angle

100+angle PQR +pRQ =180°

= 100+ 2x =180°

=2x = 80°

=x=80/2

=40°

40+40+x=180° ( sum of two interior angles =an exterior angle is 180°)

x=180-80

x=100

please mark me as brainliest

Answered by shubhankarmahashabde
0

Answer:

130°

Step-by-step explanation:

∠QPR = 80° ( VERTICALLY OPPOSITE ANGLES )

∠Q = ∠PRQ ( ANGLES OPPOSITE TO EQUAL SIDES OF A TRIAMGLE )

∠QPR + ∠Q  + ∠PRQ = 180° ( ANGLE SUM PROPERT OF A TRIANGLE )

80 + 2∠PRQ = 180

2∠PRQ = 100

∠PRQ = 50°

∠PRQ + X = 180 ( LINEAR PAIR )

X = 180 - 50 = 130°

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