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Answer:
180-80=100 (vertically opposite angle
100+angle PQR +pRQ =180°
= 100+ 2x =180°
=2x = 80°
=x=80/2
=40°
40+40+x=180° ( sum of two interior angles =an exterior angle is 180°)
x=180-80
x=100
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Answer:
130°
Step-by-step explanation:
∠QPR = 80° ( VERTICALLY OPPOSITE ANGLES )
∠Q = ∠PRQ ( ANGLES OPPOSITE TO EQUAL SIDES OF A TRIAMGLE )
∠QPR + ∠Q + ∠PRQ = 180° ( ANGLE SUM PROPERT OF A TRIANGLE )
80 + 2∠PRQ = 180
2∠PRQ = 100
∠PRQ = 50°
∠PRQ + X = 180 ( LINEAR PAIR )
X = 180 - 50 = 130°
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