Question

solve my question plz...only if u know ​

Answer 1

$\huge{\mathfrak{\underline{Question :}}} \\ \\ \textsf{An electron is moving in an orbit of a hydrogen} \\ \textsf{atom from which there can be a maximum of} \\ \textsf{six transitions. An electron is moving in an} \\ \textsf{orbit of another hydrogen atom from which} \\ \textsf{there can be a maximum of three transitions. The} \\ \textsf{ratio of the velocity of the electron in these two} \\ \textsf{orbits is} \\ \\\huge{\mathfrak{\underline{Answer :}}} \\ \\ \underline{\boxed{\sf{\textsf{Velocity of electron in hydrogen atom in nth orbit is }\frac{3}{4}.}}} \\ \\ \sf \huge{\mathfrak{\underline{Step-by-Step \: Explanation :}}} \\ \\ \textsf{Number of spectral lines obtained due to transition of electron} \\ \textsf{from nth orbit to lower orbits is} \\ \boxed{\sf N = n \frac{(n - 1)}{2} } \\ \\ \textsf{In the first case, N = 6 } \\ \sf \therefore 6 = n \frac{(n - 1)}{2} \\ \implies \sf n = 4 \\ \\ \textsf{In the second case, N = 3} \\ \sf \therefore 3 = n \frac{(n - 1)}{2} \\ \implies \sf n = 3 \\ \\ \textsf{Velocity of electron in hydrogen atom in nth orbit is} \\ \therefore \boxed{ \sf \frac{v_6}{v_3} = \frac{3}{4} } \\ \\ \underline{\large{\textbf{Thanks ..!!!}}}$

Answer 2

.•♫•heya •♫•.

number of transition is given by ,

n(n-1) /2

6 = n(n-1) /2

n= 4

also,

3 = (n' - 1)n /2

n' = 3

as, v is inversely proportional to n

therefore, v/ v' = n'/ n

= 3/ 4

❤.❤