Math, asked by aditya3895, 1 year ago

solve n^3 - n = 12n - 12

Answers

Answered by hosukus
2

n^3 - n = 12n -12

n^3 - n - 12n - 12 = 0

n(n^2 -1)- 12(n+1) = 0

n(n+1)(n-1) - 12(n+1) = 0

(n-12)(n+1)(n-1)=0

n= 1, -1, 12

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