solve no. 9 pls.....
Attachments:
Answers
Answered by
0
Answer:
Join OC
In Δ OPA and Δ OCA
OP = OC (radii of same circle)
PA = CA (length of two tangents)
AO = AO (Common)
Therefore, Δ OPA ≅ Δ OCA (By SSS congruency criterion)

Hence, ∠ 1 = ∠ 2 (CPCT)
Similarly ∠ 3 = ∠ 4
Now, ∠ PAB + ∠ QBA = 180°
2∠2 + 2∠4 = 180°
∠2 + ∠4 = 90°
∠AOB = 90° (Angle sum property
❤
Answered by
0
Answer:
I hope its helpfull....
Follow me .
Attachments:
Similar questions