Solve number thirteen for me
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Let the height of a tower be h, then;
tan 45 = (h-40)/x
x = (h-40)
tan 60 = h/x
√3x = h
x = h/√3
h-40 = h/√3
h = √3h - 40√3
√3h-h =40√3
h(√3-1) = 40√3
h = 40√3/(√3-1)
= (40√3)×(√3+1)/(√3-1)×(√3+1)
= (120+40√3)/(3-1)
H = 60+20√3 m
_____________________
tan 45 = (h-40)/x
x = (h-40)
tan 60 = h/x
√3x = h
x = h/√3
h-40 = h/√3
h = √3h - 40√3
√3h-h =40√3
h(√3-1) = 40√3
h = 40√3/(√3-1)
= (40√3)×(√3+1)/(√3-1)×(√3+1)
= (120+40√3)/(3-1)
H = 60+20√3 m
_____________________
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