Question

solve only 7 number question it is of trigonometry exercise no. 8.1 lesson no. 8
seven number hi solve Karna hai bara kuch nahi diya hai samja kya only seven number OK please give it ​

Answer 1

Step-by-step explanation:

I am using '0' instead of theta

cot 0=7/8

cos0/sin0 = 7/8

therefore

cos0= 7 and sin0= 8

i) (1+sin0)(1-sin0)/(1+cos0)(1-cos0)

(1+8)(1-8)/(1+7)(1-7) = 9*(-7)/8*(-6)

= -63/-48 = 63/48 = 21/16

ii) cot^2 0

since cot0 = 7/8

therefore cot^2 0 = (7/8)^2 = 49/64

Answer 2

Answer:

refer to the attachment for the solution.

Step-by-step explanation:

formula used : sin²∅ +cos²∅ = 1

and cos²∅/sin²= cot²∅

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