Math, asked by kira12315, 1 year ago

solve only if you know ​

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Answered by HARSHIT012
0

Sorry dont know the answer

Answered by QueenOfKnowledge
1

Answer:

Let present age of father = x

and present age of son = y

Two years ago,

x - 2 = 3(y - 2)2 ..............1

Three years hence,

x + 3 = 4(y + 3) ............2

Now, from equation 2,

x = 4(y + 3) - 3

From equation 1,

=> 4(y + 3) - 3 - 2 = 3(y - 2)2

=> 4y + 12 - 5 = 3(y2 + 4 - 4y)

=> 4y + 7 = 3y2 + 12 - 12y

=> 3y2 + 12 - 12y - 4y - 7 = 0

=> 3y2 - 16y + 5 = 0

=> (y - 5)*(3y - 1) = 0

=> y= 5, 1/3

Since age can not be in fraction,

So y = 5

From equation 2,

x + 3 = 4(5 + 3)

=> x + 3 = 4*8

=> x + 3 = 32

=> x = 32 - 3

=> x = 29

So, present age of father = 29

and present age of son = 5

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