solve. . . . . only third not second
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Where is the circuit of bulbs ...what r their values??
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Answer will be 1:2.
It is as follows :
Current is common in both the bulbs as they are connected in series, so current flow =i
Ratio of power dissipation of the bulbs= i^2R1:i^2R2
Therefore ratio of power dissipation is equal to ratio of resistance offered by bulbs = 1:2
It is as follows :
Current is common in both the bulbs as they are connected in series, so current flow =i
Ratio of power dissipation of the bulbs= i^2R1:i^2R2
Therefore ratio of power dissipation is equal to ratio of resistance offered by bulbs = 1:2
Hope it helps you....plz mark it as brainliest answer
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