Question

Solve : p2 - 6p + 36 = 0.​

Answer 1

THE QUESTION IS WRONG..

BUT IM GIVING U THE ANSWER ANYWAY

Answer 2

$p=3±3\sqrt{3}i}$

Step-by-step explanation:

The given quadratic equation:

$p^2-6p+36=0$

Here, a = 1, b = - 6 and c = 36

To fiind, the value of p = ?

∴ $D=b^{2}-4ac$

$=(-6)^{2}-4(1)(36)$

= 36 - 144

= - 108 < 0, the roots are complex possible only

∴ $p=\frac{-b±\sqrt{D}}{2a}$

$=\frac{-(-6)±\sqrt{-108}}{2(1)}$

$=\frac{6±6\sqrt{3}i}{2}$

[∵ $i^{2}=-1$]

$=3±3\sqrt{3}i}$

Hence, $p=3±3\sqrt{3}i}$