Math, asked by kulharir7, 1 year ago

Solve : p² – 6p + 36 = 0.​

Answers

Answered by sachinarora2001
1

Solve.

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P²- 6p +36=0

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Solution..

By completing square method

a =  > 1 \\  \\ b =  >  - 6 \\  \\ c =  > 36 \\  \\  d =  >  {b}^{2}  - 4 \times a \times c \\  \\ d =  >  ( - 6 {)}^{2}  - 4 \times 1 \times 36 \\  \\ d =  > 36 - 144 \\  \\ d =  >  - 108 \\  \\ d < 0 \\  \\ hence \: roots \: are\: unreal

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NOTE.

* IF (D) will be greater than 0 then there is need to define more to find zeroes by following formula.

 \boxed{ \frac{ - b +  -  \sqrt{d} }{2a} }

* After this it will be easy to find zeroes ..But in above case roots are undefined because (d) is less than zero ....

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Hope it's helps you

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