Question

Solve : p² – 6p + 36 = 0.​

Answer 1

Solve.

____________

P²- 6p +36=0

____________

Solution..

By completing square method

$a = > 1 \\ \\ b = > - 6 \\ \\ c = > 36 \\ \\ d = > {b}^{2} - 4 \times a \times c \\ \\ d = > ( - 6 {)}^{2} - 4 \times 1 \times 36 \\ \\ d = > 36 - 144 \\ \\ d = > - 108 \\ \\ d < 0 \\ \\ hence \: roots \: are\: unreal$

_________________________

NOTE.

* IF (D) will be greater than 0 then there is need to define more to find zeroes by following formula.

$\boxed{ \frac{ - b + - \sqrt{d} }{2a} }$

* After this it will be easy to find zeroes ..But in above case roots are undefined because (d) is less than zero ....

_________________________

Hope it's helps you