Chemistry, asked by prabhavbhasin, 10 months ago

electronic configuration of lead
(valency-82 nearest noble gas- Radon valency-86)??

Answers

Answered by esakhan

Answer:

can u explan ur question ..?

Answered by madihahsyed

Answer:

[Xe] 6s2 4f14 5d10 6p2

Explanation:

When writing the noble gas configuration you pick the noble gas from the previous period and right the remainder of the configuration.

1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5d6 is the electron configuration of Xenon, the noble gas in the period before Lead (Pb).

Instead of writing all of that out, we can represent that with symbol for Xenon (Xe) and write the rest of configuration up to Lead (Pb) from there. The remaining configuration is 6s2 4f14 5d10 6p2. Remember to put the symbol of the noble gas in brackets, [ ].

Putting all of that together the noble gas configuration of Lead (Pb) is [Xe] 6s2 4f14 5d10 6p2.

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