Question

Solve p2x2+(p2-q2)x-q2=0 by quadratic equation

Answer 1

Answer:

Step-by-step explanation:

Given quadratic equation is 

p²x² + ( p² - q² )x - q² = 0

dividing each term with p² ,

p²x² / p² + [ ( p² - q² ) / p² ] x - q² / p² = 0

⇒ x²  + [ 1 - q² / p² ] x - q² / p² = 0

 To find the roots split the middle term

⇒     x² + x - ( q² / p² ) x - q² / p² = 0

⇒  x ( x + 1 ) - ( q² / p² ) ( x + 1) = 0

⇒                ( x+ 1 ) ( x - q² /p² ) = 0

Therefore,

                x+1 =0  or  x - q² / p² =0

           x= -1 or       x  = q² / p²

Answer 2

Answer:

x=-1 or q²/p²

Step-by-step explanation:

Refer to picture

Plz Mark brainliest

I need them

Plz plz plz