Math, asked by divyamonga, 7 months ago

solve please I will mark the good answer Brainliest​

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Answers

Answered by himanik2005
1

Answer:

The answer is 2Y^3/25 + 2X^2Y/15.

Step-by-step explanation:

(X/3 + Y/5)^3 is of the form (A+B)^3.

(A+B)^3 = A^3 + B^3 + 3A^2B + 3AB^2

So,

(X/3 + Y/5)^3 = (X/3)^3 + (Y/5)^3 + 3(X/3)^2(Y/5) + 3(X/3)(Y/5)^2.

= X^3/27 + Y^3/125 + X^2Y/15 + XY^2/25. --------1st equation

(X/3 - Y/5)^3 is of the form (A-B)^3.

(A-B)^3 = A^3 - B^3 - 3A^2B + 3AB^2

So,

(X/3 - Y/5)^3 = (X/3)^3 - (Y/5)^3 - 3(X/3)^2(Y/5) + 3(X/3)(Y/5)^2.

= X^3/27 - Y^3/125 - X^2Y/15 + XY^2/25. -----------2nd equation

So,

(X/3 + Y/5)^3 - (X/3 - Y/5)^3 =====> 1st equation - 2nd equation.

===>

X^3/27 + Y^3/125 + X^2Y/15 + XY^2/25 - ( X^3/27 - Y^3/125 - X^2Y/15 + XY^2/25 )

===>

X^3/27 + Y^3/125 + X^2Y/15 + XY^2/25 - X^3/27 + Y^3/125 + X^2Y/15 - XY^2/25

===>

X^3/27- X^3/27 + Y^3/125 + Y^3/125 + X^2Y/15 + X^2Y/15 + XY^2/25 - XY^2/25

===>

2Y^3/25 + 2X^2Y/15.

Hope this helps!!!!!

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