solve please
kindly don't spam otherwise ..
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4
!! Hey Mate !!
your answer is --
see the attachment
【 Hope it helps you 】
your answer is --
see the attachment
【 Hope it helps you 】
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Anonymous:
srry kis liye
Nice but long method
ya i know both method
socha kong method he de du
hehehe
:-)
:D
Answered by
19
Heya.......!!!!
____________________________
This question can be easily solved by applying the property of Dot product :
- Given in the question that the angle between two vectors is 90° .
We know that = A.B = ABcosθ
In the question :- θ = 90° and Cos90° = 0 .
So we can equate the dot product equal to 0.
=> ( 2i^ + 3j^ + 8k^ ) . ( 4i^ - 4j^ + αk^ ) = 0
=> (2.4) i^.i^ - ( 3.4) j^.j^ + (8.α) k^.k^ = 0
=> 8 - 12 + 8α = 0
=> -4 + 8α. = 0
=> 8α = 4
=> α = 4 / 8
=> α = 1 / 2
We just simply equate the dot product equal to 0 because the vectors were perpendicular to each other and then taken out the Value of α
==================================
Hope It Helps You ☺
____________________________
This question can be easily solved by applying the property of Dot product :
- Given in the question that the angle between two vectors is 90° .
We know that = A.B = ABcosθ
In the question :- θ = 90° and Cos90° = 0 .
So we can equate the dot product equal to 0.
=> ( 2i^ + 3j^ + 8k^ ) . ( 4i^ - 4j^ + αk^ ) = 0
=> (2.4) i^.i^ - ( 3.4) j^.j^ + (8.α) k^.k^ = 0
=> 8 - 12 + 8α = 0
=> -4 + 8α. = 0
=> 8α = 4
=> α = 4 / 8
=> α = 1 / 2
We just simply equate the dot product equal to 0 because the vectors were perpendicular to each other and then taken out the Value of α
==================================
Hope It Helps You ☺
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