solve please please
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first rationalize a with 2-√5
and then find the value of a² - b²
it will give (a+b)²-(a-b)²
then solve it by identity a+ b and a-b
and then find the value of a² - b²
it will give (a+b)²-(a-b)²
then solve it by identity a+ b and a-b
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Answer:
Step-by-step explanation:
a = (2 -√5) / (2 + √5)
= (2-√5)² / (2+√5)(2-√5)
= 4+5-4√5 / 4-5
= 9 - 4√5 / -1
= 4√5 - 9
b = (2+√5) / (2-√5)
= (2+√5)² / (2-√5)(2+√5)
= 4+5+4√5 / 4-5
= 9 + 4√5 / -1
= -(4√5+9)
Now,
a² - b²
= (4√5-9)² - {-(4√5+9)²
= (80+81-72√5) - (80+81+72√5)
= 161-72√5-161-72√5
= -144√5
Labdha:
a to the power 2 - b to the power 2 can also be solved using identity (a-b)(a+b)
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