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In Δ ABC, right-angled at B
Using Pythagoras theorem
AC² = AB² +BC²
AC² = 576 + 49 = 625
AC = √635
AC = ±25
Now
(i) In a right angle triangle ABC where B=90° ,
Sin A = BC/AC = 7/25
CosA = AB/AC = 24/25
(ii)
Sin C = AB/AC = 24/25
Cos C = BC/AC = 7/25
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