CBSE BOARD X, asked by ensneneb, 1 year ago

solve please this question​

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Answered by Anonymous
1

SEE THE AATACHMENT YOUR ANSWER IS THIS AND I THINK IT IS CORRECT

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Answered by Anonymous
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Answer:

In Δ ABC, right-angled at B

Using Pythagoras theorem

AC² = AB² +BC²  

AC² = 576 + 49 = 625

AC = √635

AC = ±25

Now

(i) In a right angle triangle ABC where B=90° ,

Sin A = BC/AC = 7/25

CosA = AB/AC = 24/25

(ii)

Sin C = AB/AC = 24/25

Cos C = BC/AC = 7/25

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