Math, asked by kirankaur97794, 1 year ago

solve pls its urgent

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Answered by jaskaransandhep7oysc
7
Question 2
2 x square + 5x - 3
2x^2 +6x -x -3
2x ( x+3) -1 ( x +3)
2x-1 × x+3
Zeroes are 1/2 and -3

Sum of zeroes -5/2 = -b/a
Product = -3/2 = c /a

Hence proved


Question 3


Lcm of 72 , 126 , 168
72 = 3^2 × 2^3
126 = 7×2× 3^2
168=2^3 × 7 × 3

Lcm = 2^3 × 3^2 × 7 = 504


Hcf = 2×3 = 6
Lcm × hcf =3024
But product of three numbers= 126 × 168× 72 not equals to 3024


Question 4 show root three is a factor of p and q both hence they are not co primes
Singh rout 3 is irrational
When 2 is multiples with it
It is again irrational

When 5 is added then also
So it is an i
Irrational number


Question 5=
First hcf of 56 and 96
96=56 ×1 + 40
56= 40×1+16
40=16×2+8
16=8×2+ 0


So hcf is 8
Now hcf od 8 and 404
404= 8×50+4
8 =4×2
So the hcf is 4



Question 6
Product of two given zeroes that is 2+root 3 =x
2-root 3= x
(X-2)^2 - root 3 square

X^2 -4 x +4-3
X^2-4 x +1


Now divide this by given polynomial
Then u will get a term
Solve it by middle splitting

U will get the third root also


kirankaur97794: thanku so much ..sabhi solve krdie
jaskaransandhep7oysc: Yes u r welcome
avsmanoj: i didnymmm
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