Question

Solve pls someone

# How many terms of Ap 25; 28; 31; 34 are needed to give the sum 1070

Answer 1

FIRST TERM IS =25

SUM IS 1070

COMMON DIFFERENT=28-25=3

SUM OF AP IS =n/2[2a+(n-1)d]

ACCORDING TO QUESTIONS

n/2[2a+(n-1)d]=1070

REPLACING THE VALUE WE GOT

n/2[2×25+(n-1)3]=1070

n/2[50+3n-3]=1070

n/2[47+3n]=1070

n[47+3n]=1070×2

47n+3n^2=2140

3n^2+47n-2140=0

I'm sorry but u plz solve from here

split the middle term

I want to solve but I have no notebook right now.

plz forgive me