Question

solve.....
plssssssss fastttt gys

Answer 1

it does not have real roots,its roots are complex and it's conjugate.
it cannot be solve by factorisation.
apply quadratic formula for it
$9 {x}^{2} + 6x + 4 = 0 \\ \\ x1 \: 2 = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a} \\ = \frac{ - 6 + - \sqrt{36 - 144} }{18} \\ = \frac{ - 6 + - \sqrt{ - 108} }{18}$