Math, asked by Anonymous, 8 months ago

Solve plz................​

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Answered by Anonymous
9

Answer:

c) 0

Step-by-step explanation:

We know that,

x³-y³=(x-y)(x²+xy+y²)          ........(1)

Given that,

x/y+y/x= -1

(x²+y²)/xy= -1

x²+y²= -xy

x²+y²+xy=0

(x²+xy+y²)=0

Multyplying by (x-y) on both sides we get,

(x-y)(x²+xy+y²)=(x-y)×0

From (1), we get,

x³-y³=0

HOPE IT HELPS,

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Answered by ItzParth14
2

Answer:

\huge\underline\bold\red{♡AnsWeR♡}

 {x}^{2}  {y}^{2}  = 0

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