Question

Solve previous year Question of iit jee
chapter :- magnetic effect of current​

Answer 1

Answer:

B=10wb/m² option (a)

Explanation:

Given:- charge "q" = -16×10⁻¹⁸C

velocity "V"= 10m/s

electric field "E " = 10⁴V/m

So, F = q(E+V×B) or, F = fₑ+ fₘ

∴Fₑ = qE = - 16 × 10⁻¹⁸ × 10⁴ (-j)

→ 16 × 10⁻¹⁴K

• And, Fₘ = - 16 × 10⁻¹⁸ ( 10i×Bj)

• → -16 × 10⁻¹⁴ B (+k )

• And, -16×10⁻¹⁷Bk

Since, partical will continue to move along +x-axis , so resultant force is equal to zero

• fₑ + fₘ = 0

• → 16 × 10⁻¹⁴ = 16× 10⁻¹⁷ B

• → B =. 16 × 10⁻¹⁴ / 16× 10⁻¹⁷ = 10³

• → B = 10³mb/m²