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Calculate the moles of Sodium hydroxide contained in 160 g of it.
Answer = 160 g of Sodium hydroxide. 160 g of Sodium hydroxide = 1 mol × 160 / 40 = 4 mol.
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mass of 1 molecule of NaOH = 23+16+1=40g
∴ moles in 160 g NaOH = 160/40= 4 moles
so, there are 4 moles of NaOH in 160g of it
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