solve Q.3(a) fast plz i want urgrnt
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given log2to the base7= k;
log28 to the base 49=log (4*7)to the base7^2
we know that
=log (m) to the base n^k=1(log(m)to the base n)/k
=1(log(4*7)to the base7)/2;
=
(log(mn)=logm+logn)
=(log(4)to the base 7+log7 to the base 7)/2
=(2log(2)to the base 7)+1)/2
=(2k+1)/2
log28 to the base 49=log (4*7)to the base7^2
we know that
=log (m) to the base n^k=1(log(m)to the base n)/k
=1(log(4*7)to the base7)/2;
=
(log(mn)=logm+logn)
=(log(4)to the base 7+log7 to the base 7)/2
=(2log(2)to the base 7)+1)/2
=(2k+1)/2
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