Question

solve :-
Q. A 100 mH coil carries a current of 1A . energy stored in its magnetic field is
A.0.5 J
B. 0.05 J
C. 1 J
D. 0.1 J​

Answer 1

ANSWER:

The Energy stored in the magnetic Field (E) :

E = Li^2/2

Now,

L = 100 mH = 100 * 10^-3H = 0.1H

i = 1 A

So,

E = 0.1 * (1)^2/2

E = 0.05J of Energy..

Hope it helps..

Explanation:

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