Question

Solve Q2 and Q3 step by step in copy

Answer 1

We have 2 lines AB and CD which intersect each other at O such that BC = AD and BC is parallel to AD.



In triangle OCB and ODA

AD=BC
<OCB=<ODA (alternative interior angels)
<OBC=<OAD (alternative interior angles)

SO, ∆OCB ~= ∆ODA (ASA)

Therefore by corresponding parts of congruent triangle,

OC = OD

OA = OB

Hence the lines AB and CD bisect each other at O.



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