Math, asked by shubham255549, 1 year ago

Solve Q8 and Q9 and Q10

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Answers

Answered by siyara123
2
Let x=1.323
then 100x=132.3
now
100x=x+132.323-1.323
100x-x=131.000
99x=131
x=131/99
Answered by MiniDoraemon
12
Q. (8) Express 1.323 (bar on 323) in the form p/q form where 'p' and 'q' are integers and q ≠ 0

Solution :

Let,

x = 1.323323323................. (i)

1000x = 1323.323323.......... (ii)

(ii) - (i) = 1323.323..... - 1.323......

1000x - x = 1322

999x = 1322

x = 1322/999

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Q. (9) Express 0.252 (bar on 252) in the form p/q form in which 'p' and 'q' are integers and q ≠ 0

Solution :

Let,

x = 0.252252252................. (i)

1000x = 252.252252........... (ii)

(ii) - (i) = 252.252.... - 0.252252....

1000x - x = 252

999x = 252

x = 252/999 = 28/111


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And the answer of Q. (10) is in the attached image.

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