Question

solve quad. equation 9x^2-22x+8​

Answer 1

Answer:

9x^2-22x+8=(x-2)(9x-4)    

Step-by-step explanation:

Given : Expression 9x^2-22x+8

To find : Factorise the given expression?

Solution :

The solution of a quadratic equation ax^2+bx+c=0 is

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

On comparing with 9x^2-22x+8=0

a=9 , b=-22, c=8

Substitute the values in the solution,

x=\frac{-(-22)\pm\sqrt{(-22)^2-4(9)(8)}}{2(9)}

x=\frac{22\pm\sqrt{484-288}}{18}

x=\frac{22\pm\sqrt{196}}{18}

x=\frac{22\pm 14}{18}

x=\frac{11\pm 7}{9}

x=\frac{11+7}{9},\frac{11-7}{9}

x=\frac{18}{9},\frac{4}{9}

x=2,0.44

Therefore, The value of x is 2,0.44.

Factorise form is 9x^2-22x+8=(x-2)(9x-4)