solve quadratic equation 5x-1/3=6/x
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Answered by
1
5x-1/3=6/x
5x^2-1/3x=6
15x^2-x-18=0
this is solve by quadratic formula
x={-b+_root (b^2-4ac)}/2a
={1+_root (1081)}/2.15
={1+root (1081)}/30 , {1-root (1081)}/30
5x^2-1/3x=6
15x^2-x-18=0
this is solve by quadratic formula
x={-b+_root (b^2-4ac)}/2a
={1+_root (1081)}/2.15
={1+root (1081)}/30 , {1-root (1081)}/30
Answered by
1
5x-1/3 = 6/x
(15x-1)/3 = 6/x
(15x-1) x = 18
Now either 15x -1 = 18
15x = 19
x = 19/15
Or, x = 18
Hence roots of equation are 18 and 19/15.
@_@
(15x-1)/3 = 6/x
(15x-1) x = 18
Now either 15x -1 = 18
15x = 19
x = 19/15
Or, x = 18
Hence roots of equation are 18 and 19/15.
@_@
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