Math, asked by khanzain9246, 10 months ago

solve quadratic equation..(6k^2-1)​

Answers

Answered by sakshamMINGLANI
0

Step-by-step explanation:

6k^2-1=0

k^2=1/6

kis 1 by √6

Answered by Infinitum
0

(-b\pm \sqrt{b^2-4ac})/2a= 0\pm \sqrt{0^2-4*6*-1}/2*6

=(1\pm 2\sqrt{6})/12

#BAL #answerwithquality

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