Question

Solve quadratic equation:-

$1.) \: \sqrt{3} x {}^{2} + 11x + 6 \sqrt{3} = 0$
$2.) \: 3x {}^{2} - 2\sqrt{6} x +2 = 0$

Answer 1

i hope this will b be helpful to you

Answer 2

(1)

Given Equation is √3x^2 + 11x + 6√3 = 0

⇒ √3x^2 + 9x + 2x + 6√3 = 0

⇒ √3x(x + 3√3) + 2(x + 3√3) = 0

⇒ (√3x + 2)(x + 3√3) = 0

⇒ x = -2/√3, -3√3.

(2)

Given Equation is 3x^2 - 2√6x + 2 = 0

⇒ 3x^2 - √6x - √6x + 2 = 0

⇒ √3x(√3x - √2) - √2(√3x - √2) = 0

⇒ (√3x - √2)(√3x - √2) = 0

⇒ x = √2/√3, √2/√3.

Hope it helps!