Question

Solve quadratic equation :

$\sqrt{3} x {}^{2} + 10x - 8 \sqrt{3} = 0$

Answer 1

нєуα

нєяє ιѕ тнє αиѕωєя

gινєи :-

√3χ² + 10χ - 8√3

ву ѕρℓιттιиg тнє мι∂∂ℓє тєям,

=> √3χ² + 12χ - 2χ - 8√3

=> √3χ (χ + 4√3) - 2 (χ + 4√3)

=> (√3χ - 2)(χ + 4√3)

нσρє тнιѕ нєℓρѕ.

Answer 2

HEY THERE!!



Question;

$\sqrt{3} x {}^{2} + 10x - 8 \sqrt{3} = 0$

Method Of Solution;

√3x²+10x-8√3 = 0

√3x²+12x-2x-8√3 = 0

√3x(x+4√3) -2(x+4√3) = 0

•°• (x+4√3)(√3x-2) = 0

Roots of Quardratic Equation!


•°• (x+4√3)(√3x-2) = 0

(x+4√3) =0

•°• x = -4√3

Also,

(√3x -2)=0

√3x = 2

•°• x =2/√3

Additional Answer!!



$\huge{ \bold{ \tiny{rationalizing \: the \: denominator}}}$
$x = \frac{2}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } \\ \\ x = \frac{2 \sqrt{3} }{3}$



Hence, Roots of this Quardratic Equation;
x = 2√3/ 3 and -4√3