Question

Solve quadratic equation

$x {}^{2} - ( \sqrt{3} + 1)x + \sqrt{3} = 0$

Answer 1

${x}^{2} - ( \sqrt{3} + 1)x + \sqrt{3} = 0 \\ {x}^{2} - \sqrt{3} x - x + \sqrt{3} = 0 \\ x(x - \sqrt{3} ) - (x - \sqrt{3} ) = 0 \\ (x - 1)(x - \sqrt{3} ) = 0 \\ x = 1 \\ x = \sqrt{3}$

Answer 2

HEY THERE!!

Question;-

x²-(√3+1)x + 3 =0

Solving by Splitting method;

x²-(√3+1)x + 3 =0

=> x²-√3x-x+√3=0

=> x(x-√3)-1(x-√3)

=> (x-√3)(x-1)

Roots of this Equation;

(x-√3)=0
=> x=√3

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(x-1)=0

=> x=1

Hence, Roots are √3 and 1