Question

Solve (quadratic equations)
3x² + 2√3x - 8 = 0
4x² + 6√5x +10 = 0​

Answer 1

A. Factor-

1. Factor 3x2 + 6x if possible.

Look for monomial (single-term) factors first; 3 is a factor of both 3x2

and 6x and so is x . Factor them out to get 3x2+6x= 3(x2+2x1= 3x(x+2).

2. Factor x2 + x - 6 if possible.

Here we have no common monomial factors. To get the x2 term

we'll have the form (x+-)(x +-) . Since

(x+A)(x+B)= x2 + (A+B)x+ AB ,

we need two numbers A and B whose sum is 1 and whose product is -6 . Integer possibilities that will give a product of -6 are

-6and1,6and-1,-3and2, 3and-2.

The only pair whose sum is 1 is ( 3 and -2) , so the factorization is

x2 + x - 6 = ( x + 3 ) ( x - 2 ) . 3 . F a c t o r 4 x 2 - 3 x - 1 0 if p o s s i b l e

Step-by-step explanation: