solve que 24..........
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1).ABCD is a parallelogram.
So, AB= CD and AD = BC
In triangle APB and CQD,
AB = CD [ Given]
B D = B D [Common]
ABP =CDQ [ Alternate Angles]
ABP~CQD
2). BY this triangle ABP and CQD are congruent, so AP= CQ.
So, AB= CD and AD = BC
In triangle APB and CQD,
AB = CD [ Given]
B D = B D [Common]
ABP =CDQ [ Alternate Angles]
ABP~CQD
2). BY this triangle ABP and CQD are congruent, so AP= CQ.
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