Question

solve ques 10 plz help me​

Answer 1

so.. let x be length of breadth of rectangle

according to question
l = 3x - 6

in case 2 .....perimeter of rectangle = 2(l+b)
2 ( l+ x) = 148
2 ( 3x- 6 + x) = 148
4x - 6 = 74
4x = 80
x = 20

substitute value of x in l = 3x - 6
l = 3x - 6
l = 3 x 20 - 6 = 54

therefore length of rectangle is 54 cm and breadth of rectangle is 20 cm.

hope this helps!
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# bebrainly

Answer 2

$\bold{given : } \\ \\ length \: of \: a \: rectangle \: is \: 6 \: m \: less \\ \\ \: than \: 3 \: times \: its \: breadth \:$
$\bold{perimeter \: of \: a \: rectangle : } \\ \\ \underline\bold{148 \: m}$
$\bold{let : } \\ \\ breadth \:of \: a \: rectangle \: is \:\underline\bold{x \: } m$
$\bold{according \: to \: the \: question : } \\ \\\bold{ l \: = \: 3 \times x - 6}$
$\bold{formula \: for \: perimeter \: of \: a \: rectangle : } \\ \\\underline\bold{ 2 \: ( l \: + \: b \: ) }$
$148 \: m \: = \: 2 \: ( \: 3x - 6 + x \: ) \\ \\ \frac{148}{2} = ( \: 3x - 6 + x \: ) \\ \\ 74 \: = \: 3x - 6 + x \\ \\ 74 = 4x - 6 \\ \\ 4x = 74 + 6 \\ \\ 4x = 80 \\ \\ x = \frac{80}{4} \\ \\ x = 20 \: m \:$
$\bold{breadth \:of \: a \: triangle \: = \: 20\: m \: } \\ \\ length : \\ \\ 3x - 6 \\ \\ 3 \times 20 - 6 \\ \\ 60 - 6 \\ \\ 54\: m \:$
$\bold{length \: of \: a \: rectangle \: = \:54 \: m \: }$
$\\ \\ \bold{final \: outcome : } \\ \\ \underline\bold{breadth \: of \: a \: rectangle \: = \: 20\: m \: } \\ \\ \underline\bold{length \: of \: the \: rectangle \: = \: 54\: m \: }$