Question

solve ques 6 fast i will warm brainleist​

Answer 1

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HOPE THIS HELPS YOU

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Answer 2

Answer:

$\huge\purple{\sf{ \underline{{♧given\ \: : }}}}$

$\purple \bigstar \bf \frac{5}{ \sqrt{3} + \sqrt{2} }$

$\huge\purple{\sf{ \underline{{♧to \: find\ \: : }}}}$

$\purple\bigstar\bf \: {rationalising \: factor}$

$\huge\purple{\sf{ \underline{{♧solution\ \: : }}}}$

$\sf \to \frac{5 \times } { \sqrt{3} + \sqrt{2 } \times } \frac{ \sqrt{3} - \sqrt{5} }{ \sqrt{3} - \sqrt{5} }$

$\sf \to \frac{5 \sqrt{3} - 5 \sqrt{5} }{ {( \sqrt{3} )}^{2} - {( \sqrt{5} })^{2}}$

$\sf \to \frac{5 \sqrt{3} - 5 \sqrt{5} }{3 - 5}$

$\purple \to \sf \frac{5 \sqrt{3} - 5 \sqrt{5} }{ - 2}$

$\sf{ \purple {\underline {\underline{{note \ \: : }}}}}$

$\sf(x + y)(x - y) = {x}^{2} - {y}^{2}$

$\purple \bigstar \sf we \: must \: use \: this \: identity$

$\sf \: \: \: \: to \: rationalise \: the \: denominator$

$\sf{ \purple{ \underline{ \underline{{additional \: information \ \: : }}}}}$

$\sf {(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2}$

$\sf {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2}$

$\sf(x + y)(x - y) = {x}^{2} - {y}^{2}$

$\sf(x + a)(x + b) = {x}^{2} +x(a + b) + ab$

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