Question

Solve ques no. 11

Class 10th

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Answer 1

Hey dear!!

Here is yr answer....

11.

Given,

Form of a quad. polynomial,

one of the zero is 2 + √5 = α

sum of the zeros = 4

Now,

let the other zero be β

α+β = 4

2+√5+β = 4

√5 + β = 4 - 2

√5 + β = 2

β = 2 -√5

We need to take it into the order of quad equation---

use the formula ---

x²+(a+b)x + ab

= x²+(α+β)x+αβ

= x²+(2+√5+2-√5)x +( 2+√5)(2-√5)

= x² + 4x -1


Hope it hlpz....

Answer 2

hlw..
again
solu question 11..
hope ........