Question

Solve question 13and 11...plsss fast!!!!!

Answer 1

Solution 13.)

Let the numbers be 15a and 11a

HCF = 13

LCM = 2145

We know that,

Product of numbers = LCM × HCF

=> 15 a × 11 a = 13 × 2145

=> a^2 = 13 × 2145 / 11 × 15

=> a^2 = 13 × 195 / 15

=> a^2 = 13 × 13

=> a = 13

First number = 15 × 13 = 195

Second number = 11 × 13 = 143

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Solution 11.)

LCM = 64699

HCF = 97

First number = 2231

We know that,

Product of numbers = LCM ×HCF

=> Second number × 2231 = 64699 × 97

=> Second number = 64699 × 97 / 2231

=> Second number = 29 × 97

=> Second number = 2813

Answer 2

11. LCM × HCF = PRODUCT OF NUMBERS

64699 × 97 = 2231× OTHER NO.

6275803÷2231= OTHER NO.

∴ OTHER NO. =  2813

13) LET THE NUMBERS BE 15x AND 11x

LCM × HCF = PRODUCT OF NUMBERS

2145 × 13 = 11x × 15x

27885 = 165x²

x² = 27885 ÷ 165

x² = 169

x = √169 = 13

 the no. are 15x and 11x

i.e, the no. are 15×13 and 11×13

∴ the no. are 195 and 143 respectively.



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