Question

solve question 14 irrelevant answers 10 answers will be reported​

Answer 1

AnswEr-:

• $\dag{\boxed{\sf{The\:\:two\:digit\:number\:is\:31\:}}}$

Explanation -:

$\sf{Given -:}$

• The tens digit of a two digit number is three times to the unit digit .
• The sum of the number and the unit digit is 32 .

$\sf{To\:Find -:}$

• The number .

$\dag{\underline{\mathrm{ Solution\:of\:question-:}}}$

• $\sf{Let 's\:Assume -:}$

• The one's digit number be x .

• $\sf{Then -:}$

• The ten's digit number of a two digit number is three times to the unit digit-:

• $\sf{Then -:}$

• The tens digit of a two digit number is 3 x .

• Then ,

• $\frak{The\:numbers\: -:} \begin{cases} \sf{The\:unit \:digit \:number \:\:is\:= \frak{x }} & \\\\ \sf{ The\:ten's \:digit \:number \:\:is\:\:=\:\frak{3x }}\end{cases}$

• $\sf{Therefore -:}$

• $\mathrm {\dag{Original \:number \:= 10(3x)\:+ x }}$

• $\mathrm {\dag{Original \:number \:= 30x\:+ x }}$

• $\mathrm {\dag{Original \:number \:or\:Sum\:of\:number \:= \:31 x }}$

• $\sf{Given \:That\:-:}$

• The sum of the number and the unit digit is 32 .

• Or,

• $\sf{Sum \:of\:number\:+ unit \:Digit= 32}$

• $\sf{Here-:}$

• Unit Digit = x

• Sum of the number = 31 x

$\sf{According \:to\:Question \:-:}$

• $\longrightarrow{\sf{Sum \:of\:number\:+ unit \:Digit= 32}}$

• $\longrightarrow{\sf{31x\:+ x= 32}}$

• $\longrightarrow{\sf{32x\:= 32}}$

• $\longrightarrow{\sf{x= \dfrac{32}{32}}}$

• $\longrightarrow{\sf{x\:= 1}}$

Therefore,

• $\boxed{\sf{x\:= 1}}$

$\frak{Putting \:x =1\: -:} \begin{cases} \sf{The\:unit \:digit \:number \:\:is\:= \frak{x = 1 }} & \\\\ \sf{ The\:ten's \:digit \:number \:\:is\:\:=\:\frak{3x = 3 \times 1 = 3}}\end{cases}$

• $\boxed{\sf{The\:unit\:digit\:of\:two\:digit\:number\:is\:1\:and\;ten's\:digit\:number\:is\:3}}$

$\sf{Hence -:}$

• $\dag{\boxed{\sf{The\:\:two\:digit\:number\:is\:31\:}}}$

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